Electronis Discussion
0 votes

Let $f\left ( x,y \right )=\frac{ax^{2}+by^{2}}{xy},$ where $\text{a}$ and $\text{b}$ are constants. If $\frac{\partial f}{\partial x}=\frac{\partial f}{\partial y}$ at $\text{x = 1}$ and $\text{y = 2}$, then

the relation between $\text{a}$ and $\text{b}$ is

  1. $a=\frac{b}{4}$
  2. $a=\frac{b}{2}$
  3. $a=2b$
  4. $a=4b$
in Others by (1.4k points)
edited by

Please log in or register to answer this question.

Welcome to GO Electronics, where you can ask questions and receive answers from other members of the community.
1,109 questions
44 answers
42,876 users