in Network Solution Methods recategorized by
75 views
1 vote
1 vote

The current $I$ in the given network is

                  

  1. $0 \: A$
  2. $2.38\angle -96.37^{\circ}A$
  3. $2.38\angle143.63^{\circ}A$
  4. $2.38\angle-23.63^{\circ}A$
in Network Solution Methods recategorized by
1.9k points
75 views

Please log in or register to answer this question.

Welcome to GO Electronics, where you can ask questions and receive answers from other members of the community.