1 votes 1 votes The current $I$ in the given network is $0 \: A$ $2.38\angle -96.37^{\circ}A$ $2.38\angle143.63^{\circ}A$ $2.38\angle-23.63^{\circ}A$ Network Solution Methods gate2020-ec network-solution-methods + – go_editor asked Feb 13, 2020 • recategorized Nov 15, 2020 by soujanyareddy13 go_editor 1.9k points 122 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.