0 votes 0 votes The switch in the circuit in the figure is in position $P$ for a long time and then moved to position $Q$ at time $t=0$. The value of $\dfrac{dv\left ( t \right )}{dt}$ at $t=0^{+}$ is $0\:V/s$ $3\:V/s$ $-3\:V/s$ $-5\:V/s$ Others gateec-2021 + – Arjun asked Feb 19, 2021 edited Feb 25, 2021 by soujanyareddy13 Arjun 6.5k points 172 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.