1 votes 1 votes The value of the integral $\oint_c \frac{-3 z+4}{\left(z^2+4 z+5\right)} d z$ where $c$ is the circle $|z|=1$ is given by $0$ $1 / 10$ $4 / 5$ $1$ Others gate2011-ec + – admin asked Sep 3, 2022 • edited Jan 27, 2023 by Lakshman Bhaiya admin 46.4k points 98 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.