An op. amp. has an offset voltage of $1 \mathrm{mV}$ and is ideal in all other respects. If this op. amp. is used in the circuit shown in the given figure, the output voltage will be (select the nearest value)
- $1 \mathrm{mV}$
- $1 \mathrm{~V}$
- $\pm 1 \mathrm{~V}$
- $0 \mathrm{~V}$.