The $\text{JFET}$ in the circuit shown in the given figure has an $\mathrm{I}_{\mathrm{DSS}}=10 \mathrm{~mA}$ and $\mathrm{V}_{\mathrm{p}}=5 \mathrm{~V}$. The value of the resistance $\mathrm{R}_{\mathrm{s}}$ for a drain current $\mathrm{I}_{\mathrm{DS}}=6.4 \mathrm{~mA}$ is (select the nearest value)
- $150 \; \mathrm{ohms}$
- $470$ ohms
- $560$ ohms
- $1$ kilo ohm.