Electronis Discussion

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As we know when light is falling top of an object it casts the shadow at behind of the object

Here, we can see in △ABE and △CDE

∠B = ∠D & ∠E = ∠E

∴ By proportionality theorem,

$\dfrac{AB}{CD} = \dfrac{BE}{DE}$

Here, AB = ?

CD = 1.5 m

BD = 3 m

DE = 3 m

∴ $\dfrac{AB}{1.5} = \dfrac{3 + 3}{3}$

AB = $ \dfrac{6}{3} * 1.5$

AB = 3 m

∴ Height of the Lamp post is **3 m** option ** B)**

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