1 votes 1 votes The Nyquist sampling rale for the signal $s(t)=\dfrac{\sin (500 \pi t)}{\pi t} \times \dfrac{\sin (700 \pi t)}{\pi t}$ is given by $400 \mathrm{~Hz}$ $600 \mathrm{~Hz}$ $1200 \mathrm{~Hz}$ $1400 \mathrm{~Hz}$ Others gate2010-ec + – admin asked Sep 15, 2022 • edited Jan 27, 2023 by Lakshman Bhaiya admin 46.4k points 37 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.