1 votes 1 votes If $e^{y}=x^{\frac{1}{x}}$, then $y$ has a maximum at $x=e$ minimum at $x=e$ maximum at $x=e^{-1}$ minimum at $x=e^{-1}$ Calculus gate2010-ec calculus maxima-minima + – admin asked Sep 15, 2022 recategorized Jan 27, 2023 by Lakshman Bhaiya admin 46.4k points 40 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.