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If $X=1$ in the logic equation $[X+Z\{\overline{Y}+(\overline{Z}+X \overline{Y})\}]\{\overline{X}+\overline{Z}(X+Y)\}=1$, then

  1. $Y=Z$
  2. $Y=\overline{Z}$
  3. $Z=1$
  4. $Z=0$
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