2 views

If $X=1$ in the logic equation $[X+Z\{\bar{Y}+(\bar{Z}+X \bar{Y})\}]\{\bar{X}+\bar{Z}(X+Y)\}=1$, then

1. $Y=Z$
2. $Y=\bar{Z}$
3. $Z=1$
4. $Z=0$