For the circuit shown in the following figure, transistors $\text{M1}$ and $\text{M2}$ are identical $\text{NMOS}$ transistors. Assume that $\mathrm{M} 2$ is in saturation and the output is unloaded.
The current $I_{X}$ is related to $I_{\text {bias }}$ as
- $I_{X}=I_{\text {bias }}+I_{S}$
- $I_{X}=I_{\text {bias }}$
- $I_{X}=I_{\text {bias }}-I_{S}$
- $I_{X}=I_{\text {bias }}-\left(V_{D D}-\frac{V_{\text {out}}}{R_{E}}\right)$