1 votes 1 votes The $\text{3-dB}$ bandwidth of the low-pass signal $e^{-t} u(t)$, where $u(t)$ is the unit step function, is given by $\frac{1}{2 \pi} \mathrm{Hz}$ $\frac{1}{2 \pi} \sqrt{\sqrt{2}-1} \mathrm{~Hz}$ $\infty$ $1 \mathrm{~Hz}$ Others gate2007-ec + – admin asked Sep 19, 2022 • edited Feb 24, 2023 by Lakshman Bhaiya admin 46.4k points 37 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.