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**Statement for Linked Answer Questions 84 and 85**

A $30$-Volts battery with zero source resistance is connected to a coaxial line of characteristic impedance of $50$ Ohms at $t=0$ second and terminated in an unknown resistive load. The line length is such that it takes $400 \; \mu s$ for an electromagnetic wave to travel from source end to load end and vice-versa. At $t=400 \; \mu s$, the voltage at the load end is found to be $40$ Volts.

The steady-state current through the load resistance is

- $1.2$ Amps
- $0.3$ Amps
- $0.6$ Amps
- $0.4$ Amps