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**Statement for Linked Answer Questions 80 and 81**

Consider the following Amplitude Modulated (AM) signal, where $f_{m}<\mathrm{B}$

\[x_{\mathrm{AM}}(t)=10\left(1+0.5 \sin 2 \pi f_{m} t\right) \cos 2 \pi f_{c} t\]

The average side-band power for the AM signal given above is

- $25$
- $12.5$
- $6.25$
- $3.125$