1 votes 1 votes Consider the function $f(t)$ having Laplace transform $$ \text{F}(s)=\frac{\omega_0}{s^2+\omega_0^2} \operatorname{Re}[s]>0 $$ The final value of $f(t)$ would be $0$ $1$ $-1 \leq f(\infty) \leq 1$ $\infty$ Others gate2006-ec + – admin asked Sep 20, 2022 • edited Feb 25, 2023 by Lakshman Bhaiya admin 46.4k points 135 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.