0 votes 0 votes If $x=\sqrt{-1}$, then the value of $x^x$ is $e^{\frac{-\pi}{2}}$ $e^{\frac{\pi}{2}}$ $x$ $1$ Calculus gate2012-ec calculus + – Milicevic3306 asked Mar 25, 2018 • recategorized Feb 26, 2021 by Lakshman Bhaiya Milicevic3306 16.0k points 83 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.