0 votes 0 votes The minimum number of $\text{NAND}$ gates required to implement the Boolean function $\mathrm{A}+\mathrm{A} \overline{\mathrm{B}}+\mathrm{A} \overline{\mathrm{B}} \mathrm{C}$, is equal to zero $1$ $4$ $7$ Others gate1995-ec + – admin asked Sep 21, 2022 • edited Dec 1, 2023 by makhdoom ghaya admin 46.4k points 101 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.