0 votes 0 votes The Fourier transform of a signal $h(t)$ is $H(j\omega)=(2\cos\omega)(\sin2\omega)/\omega$. The value of $h(0)$ is $\frac{1}{4}$ $\frac{1}{2}$ $1$ $2$ Continuous-time Signals gate2012-ec continuous-time-signals signals-and-systems fourier-transform + – Milicevic3306 asked Mar 25, 2018 recategorized Nov 15, 2020 by gatecse Milicevic3306 16.0k points 295 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.