GATE ECE 2005 | Question: 57

Question

The given figure shows a ripple counter using positive edge triggered flip-flops. If the present state of the counter is $Q_{2} \; Q_{1} \; Q_{0}=011$, then its next state $\left(Q_{2} \; Q_{1} \; Q_{n}\right)$ will be

• A. $010$
• B. $100$
• C. $111$
• D. $101$

Comments

The question was asked for “next state (Q₂Q₁Q₀)” not ”next state (Q₂Q₁Qₙ)”, plz update the description.

Answer 1

PFA The answer in the attached image :

 

Thus, the sequence is 000 001 010 011 100 101 110 111 and repeat – Asynchronous 3-bit Up Counter.
We are given to start at 011 hence the next state is 100 viz option B.