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GATE ECE 2005 | Question-54

The Boolean expression for the truth table shown is
$$\begin{array}{|c|c|c|c|}
\hline \mathrm{A} & \mathrm{B} & \mathrm{C} & \mathrm{F} \\
\hline 0 & 0 & 0 & 0 \\
\hline 0 & 0 & 1 & 0 \\
\hline 0 & 1 & 0 & 0 \\
\hline 0 & 1 & 1 & 1 \\
\hline 1 & 0 & 0 & 0 \\
\hline 1 & 0 & 1 & 0 \\
\hline 1 & 1 & 0 & 1 \\
\hline 1 & 1 & 1 & 0 \\
\hline \end{array}$$

  1. $\mathrm{B}(\mathrm{A}+\text{C})(\overline{\mathrm{A}}+\bar{\text{C}})$
  2. $\mathrm{B}(\mathrm{A}+\overline{\mathrm{C}})(\overline{\mathrm{A}}+\mathrm{C})$
  3. $\overline{\mathrm{B}}(\mathrm{A}+\overline{\mathrm{C}})(\overline{\mathrm{A}}+\mathrm{C})$
  4. $\overline{\mathrm{B}}(\mathrm{A}+\mathrm{C})(\overline{\mathrm{A}}+\overline{\mathrm{C}})$
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