0 votes 0 votes For the circuit show in the figure, the instantaneous current $i_{i}(t)$ is $\frac{10 \sqrt{3}}{2} \angle 90^{\circ} \mathrm{Amps}$. $\frac{10 \sqrt{3}}{2} \angle-90^{\circ}$ Amps. $5 \angle 60^{\circ}$ Amps. $5 \angle-60^{\circ}$ Amps. Others gate2005-ec + – admin asked Sep 22, 2022 edited Nov 30, 2023 by makhdoom ghaya admin 46.4k points 99 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.