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GATE ECE 2012 | Question: 41
Milicevic3306
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Continuous-time Signals
Mar 25, 2018
edited
Nov 18, 2020
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soujanyareddy13
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The circuit shown is a
low pass filter with $f_{3\:dB}=\frac{1}{(R_1+R_2)C}\: rad/s$
high pass filter with $f_{3\:dB}=\frac{1}{R_1C}\: rad/s$
low pass filter with $f_{3\:dB}=\frac{1}{R_1C}\: rad/s$
high pass filter with $f_{3\:dB}=\frac{1}{(R_1+R_2)C}\: rad/s$
gate2012-ec
continuous-time-signals
digital-filter-design-techniques
Milicevic3306
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Continuous-time Signals
Mar 25, 2018
edited
Nov 18, 2020
by
soujanyareddy13
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Milicevic3306
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