edited by
83 views
0 votes
0 votes

Consider an abrupt $p$-junction. Let $V_{\text {in }}$ be the built-in potential of this junction and $\mathrm{V}_{\mathrm{R}}$ be the applied reverse bias. If the junction capacitance $\left(\mathrm{C}_{t}\right)$ is $1 \; \mathrm{pF}$ for
$V_{\text{in}}+V_{\mathrm{R}}=1 \mathrm{~V}$, then for $\mathrm{V}_{\text{in}}+\mathrm{V}_{\mathrm{R}}=4 \mathrm{~V}, \mathrm{C}_{t}$, will be

  1. $4 \; \mathrm{pF}$
  2. $2 \; \mathrm{pF}$
  3. $0.25 \; \mathrm{pF}$
  4. $0.5 \; \mathrm{pF}$
edited by

Please log in or register to answer this question.

Answer: