GATE ECE 2004 | Question: 35

Question

For the circuit shown in the figure, the initial conditions are zero. Its transfer function

$$ H(s) = \frac{V_{c}(s)}{V_{i}(s)}$$

• A. $\frac{1}{s^{2}+10^{6} s+10^{6}}$
• B. $\frac{10^{6}}{s^{2}+10^{3} s+10^{6}}$
• C. $\frac{10^{3}}{s^{2}+10^{3} s+10^{6}}$
• D. $\frac{10^{6}}{s^{2}+10^{6} s+10^{6}}$