If for a silicon $n-p-n$ transistor, the base-to-emitter voltage $\left(\mathrm{V}_{\mathrm{KE}}\right)$ is $0.7 \mathrm{~V}$ and the collector-to-base voltage $\left(\mathrm{V}_{\text{CB}}\right)$ is $0.2 \mathrm{~V}$, then the transistor is operating in the
- normal active mode
- saturation mode
- inverse active mode
- cutoff mode