edited by
80 views
0 votes
0 votes

If for a silicon $n-p-n$ transistor, the base-to-emitter voltage $\left(\mathrm{V}_{\mathrm{KE}}\right)$ is $0.7 \mathrm{~V}$ and the collector-to-base voltage $\left(\mathrm{V}_{\text{CB}}\right)$ is $0.2 \mathrm{~V}$, then the transistor is operating in the

  1. normal active mode
  2. saturation mode
  3. inverse active mode
  4. cutoff mode
edited by

Please log in or register to answer this question.

Answer: