0 votes 0 votes The transfer function $\dfrac{V_{2}(s)}{V_{1}(s)}$ of the circuit shown below is $\frac{0.5s+1}{s+1} \\ $ $\frac{3s+6}{s+2} \\ $ $\frac{s+2}{s+1} \\ $ $\frac{s+1}{s+2}$ Others gate2013-ec + – Milicevic3306 asked Mar 25, 2018 • recategorized Feb 26, 2021 by Lakshman Bhaiya Milicevic3306 16.0k points 98 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.