0 votes 0 votes The Fourier Transform of the signal $x(t)=\mathrm{e}^{-3 \mathrm{t}^{2}}$ is of the following form, where $A$ and $B$ are constants $\mathrm{A} e^{-\mathrm{B}|f|}$ $\mathrm{A} e^{-\mathrm{B} f}$ $\mathrm{A}+\mathrm{B}|f|^{2}$ $\mathrm{A} e^{-B f}$ Others gate2000-ec + – admin asked Sep 29, 2022 • edited Dec 2, 2023 by makhdoom ghaya admin 46.4k points 159 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.