Given that
$\mathcal{L}[f(t)]=\frac{s+2}{s^2+1}, \mathcal{L}[f(t)]=\frac{s^2+1}{(s+3)(s+2)}, $
$h(t)=\int_0^1 f(\tau) g(t-\tau) d \tau, \mathcal{L}[h(t)]$ is
- $\frac{s^2+1}{s+3}$
- $\frac{1}{s+3}$
- $\frac{s^2+1}{(s+3)(s+2)}+\frac{s+2}{s^2+1}$
- None of these