A voltage $1000 \sin\omega t\:\: \text{Volts}$ is applied across $YZ.$ Assuming ideal diodes, the voltage measured across $WX$ in $\text{Volts},$ is

- $\sin \omega t$
- $(\sin \omega t \:+ \mid \sin \omega t \mid)/2$
- $(\sin \omega t \: - \mid \sin \omega t \mid)/2$
- $0$ for all $t$