1 votes 1 votes The function $f(t)$ is a convolution of $t^{2}$ with $\exp \left(-t^{2} / 2\right) / \sqrt{2 \pi}$. Its derivative is $2 t$ $t^{2}$ $2 t+t e^{-t^{2} / 2}$ Does not have a simple closed form expression None of the above Calculus tifr2010 calculus derivatives + – admin asked Nov 30, 2022 • recategorized Jan 18, 2023 by Lakshman Bhaiya admin 46.4k points 107 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.