1 votes 1 votes Let $\imath=\sqrt{-1}$. Then $\imath^{\imath}$ could be $\exp (\pi / 2)$ $\exp (\pi / 4)$ Can't determine Takes infinite values Is a complex number Complex Analysis tifr2010 complex-analysis complex-number + – admin asked Nov 30, 2022 recategorized Jan 18, 2023 by Lakshman Bhaiya admin 46.4k points 76 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.