Consider two independent random variables $\text{X}$ and $\text{Y}$ having probability density functions uniform in the interval $[0,1]$. When $\alpha \geq 1$, the probability that $\max (\text{X, Y})>\alpha \min (\text{X, Y})$ is
- $1 /(2 \alpha)$
- $\exp (1-\alpha)$
- $1 / \alpha$
- $1 / \alpha^{2}$
- $1 / \alpha^{3}$