in Network Solution Methods retagged by
65 views
0 votes
0 votes

For an all-pass system $H(z)= \frac{(z^{-1}-b)}{(1-az^{-1})}$, where $\mid H(e^{-j\omega }) \mid= 1,$ for all $\omega$. If $\text{Re}(a)\neq 0, \: \text{Im}(a)\neq 0,$then $b$ equals

  1. $a$
  2. $a^{*}$
  3. $1/a^{*}$
  4. $1/a$
in Network Solution Methods retagged by
15.8k points
65 views

Please log in or register to answer this question.

Welcome to GO Electronics, where you can ask questions and receive answers from other members of the community.