0 votes 0 votes Let $f(x,y)=x^n y^m=P$. If $x$ is doubled and $y$ is halved, the new value of $f$ is $2^{n-m}P$ $2^{m-n}P$ $2(n-m)P$ $2(m-n)P$ Quantitative Aptitude gate2014-ec-4 numerical-ability functions + – Milicevic3306 asked Mar 26, 2018 • retagged Feb 26, 2021 by Lakshman Bhaiya Milicevic3306 16.0k points 88 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.