0 votes 0 votes Operators $\square,$ $\Diamond$ and $\rightarrow$ are defined by: $a\,\square\,b=\frac{a+b}{a-b};\, a\,\Diamond, b=\frac{a+b}{a-b};$ $a\,\rightarrow\, b=ab.$ Find the value of $(66\,\square\, 6)\rightarrow(66\,\Diamond, 6).$ $-2$ $-1$ $1$ $2$ Analytical Aptitude gate2015-ec-1 analytical-aptitude logical-reasoning + – Milicevic3306 asked Mar 27, 2018 retagged Mar 1, 2021 by Lakshman Bhaiya Milicevic3306 16.0k points 94 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.