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By performing cascading and/or summing/differencing operations using transfer function blocks  $G_{1}(s )$ and $G_{2}(s),$ one CANNOT realize a transfer function of the form

1. $G_{1}(s)G_{2}(s) \\$
2. $\dfrac{G_{1}(s)}{G_{2}(s)} \\$
3. $G_{1}(s)\left(\dfrac{1}{G_{1}(s)} + G_{2}(s)\right) \\$
4. $G_{1}(s)\left(\dfrac{1}{G_{1}(s)} - G_{2}(s)\right)$

Answer: