0 votes 0 votes The bilateral Laplace transform of a function $f(t) = \begin{cases} 1 & \text{if } a \leq t \leq b \\ 0 & \text{otherwise} \end{cases}$ is $\dfrac{a-b}{s} \\$ $\dfrac{e^{s}(a-b)}{s} \\$ $\dfrac{e^{-as}-e^{-bs}}{s} \\$ $\dfrac{e^{s(a-b)}}{s}$ Network Solution Methods gate2015-ec-2 network-solution-methods laplace-transform + – Milicevic3306 asked Mar 27, 2018 edited Nov 16, 2020 by soujanyareddy13 Milicevic3306 16.0k points 191 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.