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The number of $3$-digit numbers such that the digit $1$ is never to the immediate right of $2$ is

  1. $781$
  2. $791$
  3. $881$
  4. $891$
in Numerical Ability by (2.7k points)
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1 Answer

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Total Possible 3 digit number that can be formed is 900 (since we can’t place 0 in front so 9 * 10 * 10).

now given condition that 2 is in right of 1 can be satisfied if number are placed in  (x 2 1) or  (2 1 x) order. so since 9 numbers can be placed in former order and 10 in later. so answer = 900 – 10 – 9 = 881. Option C is correct.

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