0 votes 0 votes The Laplace transform of the casual periodic square wave of period $T$ shown in the figure below is $F(S) = \frac{1}{1+e^{-sT/2}} \\$ $F(S) =\frac{1}{s(1+e^{-sT/2})} \\$ $F(S) = \frac{1}{s(1-e^{-sT})} \\$ $F(S) = \frac{1}{1-e^{-sT}}$ Network Solution Methods gate2016-ec-1 network-solution-methods laplace-transform + – Milicevic3306 asked Mar 27, 2018 edited Nov 16, 2020 by soujanyareddy13 Milicevic3306 16.0k points 142 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.