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In the circuit shown below, $V_{s}$ is a constant voltage source and $I_{L}$ is a constant current load.

The value of $I_{L}$ that maximizes the power absorbed by the constant current load is

1. $\frac{V_{S}}{4R} \\$
2. $\frac{V_{S}}{2R} \\$
3. $\frac{V_{S}}{R} \\$
4. $\infty$

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