In the circuit shown below, $V_{s}$ is a constant voltage source and $I_{L}$ is a constant current load.

The value of $I_{L}$ that maximizes the power absorbed by the constant current load is

- $\frac{V_{S}}{4R} \\$
- $\frac{V_{S}}{2R} \\$
- $\frac{V_{S}}{R} \\$
- $\infty$