Milicevic3306
asked
in Differential Equations
Mar 28, 2018
recategorized
Mar 1, 2021
by Lakshman Patel RJIT

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The particular solution of the initial value problem given below is

$$\frac{d^2y}{dx^2}+12\frac{dy}{dx}+36y=0\hspace{0.3cm} \text{ with } \hspace{0.3cm}y(0)=3\hspace{0.3cm} \text{ and }\hspace{0.3cm} \frac{dy}{dx} \bigg| _{x=0} =-36$$

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