GO Electronics
Login
Register
Dark Mode
Brightness
Profile
Edit Profile
Messages
My favorites
My Updates
Logout
Recent questions tagged gate2008-ec
1
votes
0
answers
81
GATE ECE 2008 | Question: 81
In the following transistor circuit, $V_{B E}=0.7 \mathrm{~V}, r_{e}=25 \; \mathrm{mV} / I_{E},$ and $\beta$ and all the capacitances are very large. The mid-band voltage gain of the amplifier is approximately $-180$ $-120$ $-90$ $-60$
In the following transistor circuit, $V_{B E}=0.7 \mathrm{~V}, r_{e}=25 \; \mathrm{mV} / I_{E},$ and $\beta$ and all the capacitances are very large.The mid-band voltage ...
admin
46.4k
points
28
views
admin
asked
Sep 17, 2022
Others
gate2008-ec
+
–
1
votes
0
answers
82
GATE ECE 2008 | Question: 82
In the following circuit, the comparator output is logic $\text{ 1 }$ if $\mathrm{V}_{1}>\mathrm{V}_{2}$ and is logic $\text{ 0 }$ ... ) are the counter outputs. The counter starts from the clear state. The stable reading of the LED displays is $06$ $07$ $12$ $13$
In the following circuit, the comparator output is logic $\text{“1”}$ if $\mathrm{V}_{1}>\mathrm{V}_{2}$ and is logic $\text{“0”}$ otherwise. The D/A conversion i...
admin
46.4k
points
62
views
admin
asked
Sep 17, 2022
Others
gate2008-ec
+
–
1
votes
0
answers
83
GATE ECE 2008 | Question: 83
In the following circuit, the comparator output is logic $\text{ 1 }$ if $\mathrm{V}_{1}>\mathrm{V}_{2}$ and is logic $\text{ 0 }$ otherwise. The D/A conversion is done as per the relation $V_{\mathrm{DAC}}=\displaystyle{}\sum_{n=0}^{3} 2^{n-1} b_{n}$ ... magnitude of the error between $V_{D A C}$ and $V_{i n}$ at steady state in volts is $0.2$ $0.3$ $0.5$ $1.0$
In the following circuit, the comparator output is logic $\text{“1”}$ if $\mathrm{V}_{1}>\mathrm{V}_{2}$ and is logic $\text{“0”}$ otherwise. The D/A conversion i...
admin
46.4k
points
28
views
admin
asked
Sep 17, 2022
Others
gate2008-ec
+
–
1
votes
0
answers
84
GATE ECE 2008 | Question: 84
The impulse response $h(t)$ of a linear time-invariant continuous time system is given by $h(t)=\exp (-2 t) u(t)$, where $u(t)$ denotes the unit step function. The frequency response $H(\omega)$ of this system in terms of angular frequency $\omega$ ... $\frac{\sin (\omega)}{\omega}$ $\frac{1}{2+j \omega}$ $\frac{j \omega}{2+j \omega}$
The impulse response $h(t)$ of a linear time-invariant continuous time system is given by $h(t)=\exp (-2 t) u(t)$, where $u(t)$ denotes the unit step function.The frequen...
admin
46.4k
points
29
views
admin
asked
Sep 17, 2022
Others
gate2008-ec
+
–
1
votes
0
answers
85
GATE ECE 2008 | Question: 85
The impulse response $h(t)$ of a linear time-invariant continuous time system is given by $h(t)=\exp (-2 t) u(t)$, where $u(t)$ denotes the unit step function. The output of this system, to the sinusoidal input $x(t)=2 \cos (2 t)$ for all time $t,$ is $0$ $2^{-0.25} \cos (2 t-0.125 \pi)$ $2^{-0.5} \cos (2 t-0.125 \pi)$ $2^{-0.5} \cos (2 t-0.25 \pi)$
The impulse response $h(t)$ of a linear time-invariant continuous time system is given by $h(t)=\exp (-2 t) u(t)$, where $u(t)$ denotes the unit step function.The output ...
admin
46.4k
points
34
views
admin
asked
Sep 17, 2022
Others
gate2008-ec
+
–
Page:
« prev
1
2
3
GO Electronics
Email or Username
Show
Hide
Password
I forgot my password
Remember
Log in
Register