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GATE ECE 2014 Set 1 | Question: 15
The Boolean expression $(X+Y)(X+\overline{Y}) + \overline{(X\;\overline{Y}) + \overline{X}}$ simplifies to $X$ $Y$ $XY$ $X+Y$

answered in Digital Circuits Jan 5, 2021

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1 answer

2

GATE ECE 2018 | Question: 31
A four-variable Boolean function is realized using $4\times 1$ multiplexers as shown in the figure. The minimized expression for $\text{F(U,V,W,X)}$ is $\left ( UV+\overline{U}\:\overline{V}\right )\overline{W}$ ... $\left ( U\:\overline{V}+\overline{U}\:V\right )\left (\overline{W}\: \overline{X}+\overline{W}\:X\right )$

answered in Number Representations Jan 5, 2021

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3

GATE ECE 2020 | Question: 10
The figure below shows a multiplexer where $S_{1}$ and $S{2}$ are the select lines, $I_{0}$ to $I_{3}$ are the input data lines, $\text{EN}$ is the enable line, and $\text{F(P, Q, R)}$ is the output. $\text{F}$ is $PQ+\overline{Q}R.$ $PQ+Q\overline{R}.$ $P\overline{Q}R+\overline{P}Q.$ $\overline{Q}+PR.$

answered in Digital Circuits Jan 5, 2021

368 views