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In the circuit shown, if $v(t)=2 \sin(1000\: t)$ volts, $R=1\:k \Omega$ and $C=1\:\mu F,$ then the steady-state current $i(t)$, milliamperes (mA), is

  1. $\sin(1000\: t)+ \cos(1000\: t)$
  2. $2 \sin(1000\: t) +2 \cos(1000\: t)$
  3. $3 \sin(1000\: t) + \cos(1000\: t)$
  4. $\sin(1000\: t) +3 \cos(1000\: t)$
in Network Solution Methods by (1.4k points)
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