in Differential Equations retagged by
67 views
0 votes
0 votes

A curve passes through the point $\left ( x=1,y=0 \right )$ and satisfies the differential equation $\dfrac{\mathrm{dy} }{\mathrm{d} x}=\dfrac{x^{2}+y^{2}}{2y}+\dfrac{y}{x}.$ The equation that describes the curve is 

  1. $\ln\left (1+\dfrac{y^{2}}{x^{2}}\right)=x-1$
  2. $\dfrac{1}{2}\ln\left (1+\dfrac{y^{2}}{x^{2}}\right)=x-1$
  3. $\ln\left (1+\dfrac{y}{x}\right)=x-1$
  4. $\dfrac{1}{2}\ln\left (1+\dfrac{y}{x}\right)=x-1$
in Differential Equations retagged by
by
1.5k points
67 views

Please log in or register to answer this question.

Welcome to GO Electronics, where you can ask questions and receive answers from other members of the community.