1 votes 1 votes The sum of $n$ terms of the series $4+44+444+\ldots .$ is $(4 / 81)\left[10^{n+1}-9 n-1\right]$ $(4 / 81)\left[10^{n-1}-9 n-1\right]$ $(4 / 81)\left[10^{n+1}-9 n-10\right]$ $(4 / 81)\left[10^{n}-9 n-10\right]$ Quantitative Aptitude gate2011-ec quantitative-aptitude sequence-series + – admin asked Sep 3, 2022 • recategorized Jan 27, 2023 by Lakshman Bhaiya admin 46.4k points 189 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.