Electronis Discussion

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We know that the** Divisibility Rule of 3 says that if the sum of the digits ****are**** a multiple of 3 or can be divided by 3 then the digit itself can be divided by 3**

Now, we're assuming the missing number to be x

So, Sum = 7 + 1 + 5 + x + 4 + 2 + 3 = 22 + x

Now, we'll be verifying all the options

Option A) 0 , then Sum = 22 -----> **Discarded** as 22 cannot be divided by 3

Option B) 2 , then Sum = 24 -----> **Accepted** as 24 is a multiple of 3

Option C) 5 , then Sum = 27 -----> **Accepted** as 27 is a multiple of 3

Option D) 6 , then Sum = 28 -----> **Discarded** as 28 cannot be divided by 3

Now the question tells us that in the place of x we can only accept the smallest whole number

So, the feasible answer would be 2 i.e **option B)**

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