If the number $715\blacksquare423$ is divisible by $3(\blacksquare$  denotes the missing digit in the thousandths place$),$ then the smallest whole number in the place of $\blacksquare$ is _________.

1. $0$
2. $2$
3. $5$
4. $6$

edited

We know that the Divisibility Rule of 3 says that if the sum of the digits are a multiple of 3 or can be divided by 3 then the digit itself can be divided by 3

Now, we're assuming the missing number to be x

So, Sum = 7 + 1 + 5 + x + 4 + 2 + 3 = 22 + x

Now, we'll be verifying all the options

Option A) 0 , then  Sum = 22 -----> Discarded as 22 cannot be divided by 3

Option B) 2 , then  Sum = 24 -----> Accepted as 24 is a multiple of  3

Option C) 5 , then  Sum = 27 -----> Accepted as 27 is a multiple of 3

Option D) 6 , then  Sum = 28 -----> Discarded as 28 cannot be divided by 3

Now the question tells us that in the place of x we can only accept the smallest whole number

So, the feasible answer would be 2 i.e option B)

by (540 points)