1 1 vote Let $f(x)=\sqrt{x^{2}-4 x+4},$ for $x \in(-\infty, \infty)$. Here, $\sqrt{y}$ denotes the non-negative square root of $y$ when $y$ is non-negative. Then, which of the following is $\text{TRUE}?$ $f(x)$ is not continuous but differentiable $f(x)$ is continuous and differentiable $f(x)$ is continuous but not differentiable $f(x)$ is neither continuous nor differentiable None of the above Calculus tifrece2019 calculus continuity-and-differentiability + – admin 245 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.
