1 1 vote Let $\lim _{n \rightarrow \infty} x_{n}=x$. Then which of the following is $\text{TRUE.}$ There exists an $n_{0}$, such that for all $n>n_{0},\left|x_{n}-x\right|=0$. There exists an $n_{0}$, such that for all $n>n_{0},\left|x_{n}-x\right| \leq \epsilon$ for any $\epsilon>0$. For every $\epsilon>0$, there exists an $n_{0}$, such that for all $n>n_{0},\left|x_{n}-x\right| \leq \epsilon$. There exists an $n_{0}$, such that for all $n>n_{0},\left|\frac{x_{n}}{x}\right| \leq \epsilon$ for any $\epsilon>0$. None of the above. Calculus tifr2011 calculus limits + – admin 295 views answer comment Share Follow Add Sync Questions Print 0 reply Please log in or register to add a comment.